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x^2+.00044x-0.000022=0
We add all the numbers together, and all the variables
x^2+.00044x-5-2.2E=0
We add all the numbers together, and all the variables
x^2+.00044x-10.98022002261=0
a = 1; b = .00044; c = -10.98022002261;
Δ = b2-4ac
Δ = .000442-4·1·(-10.98022002261)
Δ = 43.92088028404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.00044)-\sqrt{43.92088028404}}{2*1}=\frac{-0.00044-\sqrt{43.92088028404}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.00044)+\sqrt{43.92088028404}}{2*1}=\frac{-0.00044+\sqrt{43.92088028404}}{2} $
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